Enter the coefficient and variable of the linear equation in the augmented matrix calculator, and the tool will find the solution of the linear equation.
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The augmented matrix calculator solves systems of linear equations using the Gauss-Jordan elimination method.
An augmented matrix is formed by combining the coefficient matrix and the constants column of a system of linear equations. It provides a compact way to solve the system using matrix operations. The number of rows in the augmented matrix equals the number of equations (or variables) in the system.
Consider a system of three linear equations:
a₁x + b₁y + c₁z = d₁
a₂x + b₂y + c₂z = d₂
a₃x + b₃y + c₃z = d₃
Coefficient Matrix (A):
$$ A = \begin{bmatrix} a_1 & b_1 & c_1 \\ a_2 & b_2 & c_2 \\ a_3 & b_3 & c_3 \end{bmatrix} $$
Constants Column (B):
$$ B = \begin{bmatrix} d_1 \\ d_2 \\ d_3 \end{bmatrix} $$
Variables (X):
$$ X = \begin{bmatrix} x \\ y \\ z \end{bmatrix} $$
The augmented matrix is denoted as [A | B].
We solve the system using Gauss-Jordan elimination, which reduces the augmented matrix to Reduced Row Echelon Form (RREF).
Solve the system:
3x + 5y = 10
7x + 9y = 15
$$ \begin{bmatrix} 3 & 5 & 10 \\ 7 & 9 & 15 \end{bmatrix} $$
$$ R_1 = \frac{R_1}{3} \Rightarrow \begin{bmatrix} 1 & 5/3 & 10/3 \\ 7 & 9 & 15 \end{bmatrix} $$
$$ R_2 = R_2 - 7R_1 \Rightarrow \begin{bmatrix} 1 & 5/3 & 10/3 \\ 0 & -8/3 & -25/3 \end{bmatrix} $$
$$ R_2 = \left(-\frac{3}{8}\right) R_2 \Rightarrow \begin{bmatrix} 1 & 5/3 & 10/3 \\ 0 & 1 & 25/8 \end{bmatrix} $$
$$ R_1 = R_1 - \frac{5}{3}R_2 \Rightarrow \begin{bmatrix} 1 & 0 & -15/8 \\ 0 & 1 & 25/8 \end{bmatrix} $$
The resulting RREF matrix gives the solution:
x = -15/8, y = 25/8
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