The calculator will calculate the initial and final values for pressure and temperature by employing Gay Lussac’s law equation.
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An online free Gay-Lussac’s Law calculator helps you instantly determine gas parameters in an isochoric (constant volume) process. It allows you to analyze the behavior of gas pressure and temperature while keeping the volume constant.
In 1802, Sir Gay-Lussac proposed a law describing gas expansion:
“For an ideal gas, the pressure of the gas is directly proportional to its temperature when the volume is held constant.”
This calculator can analyze pressure and temperature changes instantly.
Mathematically:
$$ \frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}} $$
You can also calculate moles of gas and total volume using the Gay-Lussac’s Law calculator. For pressure-volume relationships, refer to the Boyle’s Law calculator, and for temperature-volume relations, use the Charles’s Law calculator.
Using Boyle’s and Charles’s laws:
Boyle’s Law: $$ P_1 \times V_1 = P_2 \times V $$
Charles’s Law: $$ T_1 \times V_2 = T_2 \times V $$
Equating the volumes:
$$ \frac{P_1 \times V_1}{P_2} = \frac{T_2 \times V_2}{T_1} = k $$
Hence: $$ P \propto T \quad \text{or} \quad P = k \times T $$
The explosion generates high pressure propelling the bullet. Use the calculator to estimate instantaneous pressure.
In a tire, pressure increases with temperature proportionally and decreases when cooled.
Lowering temperature reduces the pressure inside a balloon, illustrating Gay-Lussac’s Law.
Heating increases internal pressure due to the direct relationship between temperature and pressure.
Find the final pressure given:
Solution:
$$ \frac{P_1}{T_1} = \frac{P_2}{T_2} $$
$$ \frac{12}{23} = \frac{P_2}{4} $$
$$ P_2 = \frac{4 \times 12}{23} = 7.66 \text{ Pa} $$
Find the initial pressure given:
Solution:
$$ \frac{P_1}{23} = \frac{9}{34} $$
$$ P_1 = \frac{9 \times 23}{34} = 6.08 \text{ Pa} $$
Temperature and pressure are directly related in a fixed volume. However, in the atmosphere, temperature increase causes gas expansion, lowering pressure locally.
No, atmospheric pressure decreases with altitude due to reduced air density and gravitational pull.
Lower altitudes generally have higher pressure due to denser air and heat variations from solar heating.
High pressure often occurs in cooler regions where gas molecules are less spread out.
Rain occurs in low-pressure conditions where water vapor condenses and precipitates.
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