Choose the type of formula and enter the values accordingly into the calculator to measure the length of a curve.
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The Length of Curve Calculator finds the arc length of a curve over a given interval. It works with various types of curves, including Explicit, Parameterized, Polar, and Vector curves.
The length of a curve represents the total distance covered by an object moving from one point to another over a time interval [a, b]. It is also referred to as the arc length of a function.
Example: Consider the function y = f(x) = x² over the interval [2, 4].
The general formula for an explicit curve is:
$$ L = \int_a^b \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \, dx $$
For a function y = f(x) from x = a to x = b:
$$ \text{Arc length} = \int_a^b \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \, dx $$
If the curve is given as x = f(t) and y = g(t) over t = a to t = b:
$$ \text{Arc length} = \int_a^b \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} \, dt $$
For a polar function r = r(t) with t ∈ [a, b]:
$$ L = \int_a^b \sqrt{r(t)^2 + \left(r'(t)\right)^2} \, dt $$
For a 3D vector curve x = x(t), y = y(t), z = z(t) over t ∈ [a, b]:
$$ L = \int_a^b \sqrt{\left(x'(t)\right)^2 + \left(y'(t)\right)^2 + \left(z'(t)\right)^2} \, dt $$
Find the length of the vector curve:
Step 1: Compute derivatives:
Step 2: Set up the integral:
$$ L = \int_2^5 \sqrt{(51t^2 + 30t - 13)^2 + (57t^2 + 4t - 9)^2 + (18t^2 + 14t - 7)^2} \, dt $$
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